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Q.

What is the force between the plates of a capacitor having a potential difference of V. (d-distance between the plates, A – area of the plate)

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a

$\frac{1}{2} \in_{0} \frac{V^{2}}{A^{2}} d$

b

$\in_{0} \frac{V^{2}}{A^{2}} d$

c

$\in_{0} \frac{V^{2}}{d^{2}} A$

d

$\frac{1}{2} \in_{0} \frac{V^{2}}{d^{2}} A$

answer is C.

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Detailed Solution

Force between the plates of a parallel plate capacitor is given by

$F = \frac{1}{2} \in_{0} E^{2} A$

$E = \frac{V}{d}$

$∴$ F = $\frac{1}{2} \in_{0} \frac{V^{2}}{d^{2}} A$

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