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Q.

What is the force of gravity between a 3 kg newborn baby and a 75 kg doctor standing 1 maway?


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a

3.5×10-7 N

b

6×10-4 N

c

2×10-6 N   

d

1.5×10-8 N 

answer is D.

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Detailed Solution

The force of gravity between a 3 kg newborn baby and a 75 kg doctor standing 1 m away is1.5×10-8 N.
Given,
Mass of baby, m1=3 kg
Mass of doctor, m2=75 kg
Separation distance, r=1 m
Universal law of gravity states, “Every particle attracts every other particle in the universe with a force that is directly proportional to the product of the masses and inversely proportional to the square of the distance between them.” Mathematically the gravitational force (F) is given by
F=Gm1m2r2
where G is the universal gravitation constant, m1 is the mass of the first object, m2 is the mass of second object and r is the distance between them.
On substituting the values, we get
F=(6.67×10-11)(3)(75)12
F= 1.5×10-8 N
 
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