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What is the formula of area of triangle?
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Detailed Solution
The area of a triangle represents the amount of space enclosed within its three sides. Understanding different formulas for calculating triangle area is essential for geometry, trigonometry, and practical applications in engineering, architecture, and physics.
Triangle Area Formulas
Formula Type | Formula | When to Use | Variables Explanation | Example |
Basic Area Formula | A = ½ × base × height | When base and perpendicular height are known | base = any side length<br>height = perpendicular distance to base | Base = 8 cm, Height = 6 cm<br>Area = ½ × 8 × 6 = 24 cm² |
Heron's Formula | A = √[s(s-a)(s-b)(s-c)] | When all three sides are known | a, b, c = side lengths<br>s = semi-perimeter = (a+b+c)/2 | Sides: 3, 4, 5 cm<br>s = (3+4+5)/2 = 6<br>Area = √[6(6-3)(6-4)(6-5)] = 6 cm² |
Right Triangle Formula | A = ½ × leg₁ × leg₂ | When two perpendicular sides are known | leg₁, leg₂ = perpendicular sides (not hypotenuse) | Legs: 3 cm, 4 cm<br>Area = ½ × 3 × 4 = 6 cm² |
Equilateral Triangle Formula | A = (√3/4) × side² | When all sides are equal | side = length of any side | Side = 6 cm<br>Area = (√3/4) × 6² = 9√3 ≈ 15.59 cm² |
Isosceles Triangle Formula | A = (b/4) × √(4a² - b²) | When two sides are equal | a = equal sides length<br>b = base length | Equal sides = 5 cm, Base = 6 cm<br>Area = (6/4) × √(4×25 - 36) = 12 cm² |
Using Two Sides and Included Angle | A = ½ × a × b × sin(C) | When two sides and included angle are known | a, b = side lengths<br>C = angle between sides a and b | Sides: 4, 6 cm, Angle = 60°<br>Area = ½ × 4 × 6 × sin(60°) = 6√3 cm² |
Using Coordinates | **A = ½ | x₁(y₂-y₃) + x₂(y₃-y₁) + x₃(y₁-y₂) | ** | When three vertices coordinates are known |
Using Vector Cross Product | **A = ½ | u⃗ × v⃗ | ** | When two sides are represented as vectors |
Using Circumradius | A = (abc)/(4R) | When all sides and circumradius are known | a, b, c = side lengths<br>R = circumradius | Sides: 3, 4, 5 cm, R = 2.5 cm<br>Area = (3×4×5)/(4×2.5) = 6 cm² |
Using Inradius | A = r × s | When inradius and semi-perimeter are known | r = inradius<br>s = semi-perimeter | Inradius = 2 cm, Semi-perimeter = 6 cm<br>Area = 2 × 6 = 12 cm² |
Using Median Length | A = (4/3) × √[s_m(s_m-m_a)(s_m-m_b)(s_m-m_c)] | When all three medians are known | m_a, m_b, m_c = median lengths<br>s_m = (m_a+m_b+m_c)/2 | Complex calculation - typically used in advanced problems |
Special Triangle Formulas
Scalene Triangle (All sides different)
- Primary Formula: Use Heron's formula or coordinate method
- Alternative: A = ½ × a × b × sin(C) when angle is known
Right-Angled Triangle
- Hypotenuse Known: A = ½ × √[(a+b+c)(-a+b+c)(a-b+c)(a+b-c)]/2
- Using Trigonometry: A = ½ × base × height = ½ × a × b (where a, b are legs)
Obtuse Triangle
- Same formulas apply: Use Heron's formula or sine formula
- Note: One angle > 90°, but area calculations remain the same
Quick Reference for Common Triangles
Triangle Type | Quick Formula | Key Characteristics |
3-4-5 Right Triangle | A = 6 square units | Classic Pythagorean triple |
30-60-90 Triangle | A = (side²√3)/4 | Angles: 30°, 60°, 90° |
45-45-90 Triangle | A = side²/2 | Isosceles right triangle |
Equilateral Triangle | A = (side²√3)/4 | All angles = 60°, all sides equal |
Practice Problems
Problem 1: Basic Formula
Find the area of a triangle with base 10 cm and height 8 cm.
Solution: A = ½ × 10 × 8 = 40 cm²
Problem 2: Heron's Formula
Find the area of a triangle with sides 5 cm, 12 cm, and 13 cm.
Solution: s = (5+12+13)/2 = 15 A = √[15(15-5)(15-12)(15-13)] = √[15×10×3×2] = 30 cm²
Problem 3: Sine Formula
Find the area of a triangle with sides 6 cm and 8 cm, with an included angle of 45°.
Solution: A = ½ × 6 × 8 × sin(45°) = ½ × 6 × 8 × (√2/2) = 12√2 ≈ 16.97 cm²
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