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Q.

What is the formula of area of triangle?

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Detailed Solution

The area of a triangle represents the amount of space enclosed within its three sides. Understanding different formulas for calculating triangle area is essential for geometry, trigonometry, and practical applications in engineering, architecture, and physics.

Triangle Area Formulas

Formula TypeFormulaWhen to UseVariables ExplanationExample
Basic Area FormulaA = ½ × base × heightWhen base and perpendicular height are knownbase = any side length<br>height = perpendicular distance to baseBase = 8 cm, Height = 6 cm<br>Area = ½ × 8 × 6 = 24 cm²
Heron's FormulaA = √[s(s-a)(s-b)(s-c)]When all three sides are knowna, b, c = side lengths<br>s = semi-perimeter = (a+b+c)/2Sides: 3, 4, 5 cm<br>s = (3+4+5)/2 = 6<br>Area = √[6(6-3)(6-4)(6-5)] = 6 cm²
Right Triangle FormulaA = ½ × leg₁ × leg₂When two perpendicular sides are knownleg₁, leg₂ = perpendicular sides (not hypotenuse)Legs: 3 cm, 4 cm<br>Area = ½ × 3 × 4 = 6 cm²
Equilateral Triangle FormulaA = (√3/4) × side²When all sides are equalside = length of any sideSide = 6 cm<br>Area = (√3/4) × 6² = 9√3 ≈ 15.59 cm²
Isosceles Triangle FormulaA = (b/4) × √(4a² - b²)When two sides are equala = equal sides length<br>b = base lengthEqual sides = 5 cm, Base = 6 cm<br>Area = (6/4) × √(4×25 - 36) = 12 cm²
Using Two Sides and Included AngleA = ½ × a × b × sin(C)When two sides and included angle are knowna, b = side lengths<br>C = angle between sides a and bSides: 4, 6 cm, Angle = 60°<br>Area = ½ × 4 × 6 × sin(60°) = 6√3 cm²
Using Coordinates**A = ½x₁(y₂-y₃) + x₂(y₃-y₁) + x₃(y₁-y₂)**When three vertices coordinates are known
Using Vector Cross Product**A = ½u⃗ × v⃗**When two sides are represented as vectors
Using CircumradiusA = (abc)/(4R)When all sides and circumradius are knowna, b, c = side lengths<br>R = circumradiusSides: 3, 4, 5 cm, R = 2.5 cm<br>Area = (3×4×5)/(4×2.5) = 6 cm²
Using InradiusA = r × sWhen inradius and semi-perimeter are knownr = inradius<br>s = semi-perimeterInradius = 2 cm, Semi-perimeter = 6 cm<br>Area = 2 × 6 = 12 cm²
Using Median LengthA = (4/3) × √[s_m(s_m-m_a)(s_m-m_b)(s_m-m_c)]When all three medians are knownm_a, m_b, m_c = median lengths<br>s_m = (m_a+m_b+m_c)/2Complex calculation - typically used in advanced problems

Special Triangle Formulas

Scalene Triangle (All sides different)

  • Primary Formula: Use Heron's formula or coordinate method
  • Alternative: A = ½ × a × b × sin(C) when angle is known

Right-Angled Triangle

  • Hypotenuse Known: A = ½ × √[(a+b+c)(-a+b+c)(a-b+c)(a+b-c)]/2
  • Using Trigonometry: A = ½ × base × height = ½ × a × b (where a, b are legs)

Obtuse Triangle

  • Same formulas apply: Use Heron's formula or sine formula
  • Note: One angle > 90°, but area calculations remain the same

Quick Reference for Common Triangles

Triangle TypeQuick FormulaKey Characteristics
3-4-5 Right TriangleA = 6 square unitsClassic Pythagorean triple
30-60-90 TriangleA = (side²√3)/4Angles: 30°, 60°, 90°
45-45-90 TriangleA = side²/2Isosceles right triangle
Equilateral TriangleA = (side²√3)/4All angles = 60°, all sides equal

Practice Problems

Problem 1: Basic Formula

Find the area of a triangle with base 10 cm and height 8 cm.

Solution: A = ½ × 10 × 8 = 40 cm²

Problem 2: Heron's Formula

Find the area of a triangle with sides 5 cm, 12 cm, and 13 cm.

Solution: s = (5+12+13)/2 = 15 A = √[15(15-5)(15-12)(15-13)] = √[15×10×3×2] = 30 cm²

Problem 3: Sine Formula

Find the area of a triangle with sides 6 cm and 8 cm, with an included angle of 45°.

Solution: A = ½ × 6 × 8 × sin(45°) = ½ × 6 × 8 × (√2/2) = 12√2 ≈ 16.97 cm²

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What is the formula of area of triangle?