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What is the freezing point of a solution containing 8.1 g HBr in 100 g water assuming the acid to be 90% ionised ( $K_{f}$ for water = 1.86 K ${molality}^{- 1}$ )

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$0^{o} C$

$0 . 85^{o} C$

$- {3.53}^{o} C$

$- {0.35}^{o} C$

answer is B.

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Detailed Solution

$i = 1 + α [n - 1] i = 1 + 0.9 [2 - 1] i = 1.9$

$\begin{array}{l} {ΔT}_{f} = {iK}_{f} \times m = 1 .9 \times 1 .86 \times \frac{8 .1}{81} \times \frac{1000}{100} = 3 {.53}^{o} C \\ T_{f} = - 3 {.53}^{o} C \end{array}$

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