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Q.

What is the frequency of revolution of electron present in 2nd Bohr's orbit of H-atom?

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a

4.065 x 1016 s-1

b

1.016 x 1016 s-1

c

1.626 x 1015 s-1

d

8.2 x 1014 s-1

answer is D.

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Detailed Solution

Frequency of revolution
= velocity in second orbit V22πr2=1.082×106ms12×π×2.12×1010m=8.2×1014s1

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