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Q.

What is the general formula of the homologous series of carboxylic acids?
I) Methanoic acid, $H C O_{2} H$ II) Ethanoic acid, $C H_{3} C O_{2} H$
III) Propanoic acid, $C_{2} H_{5} C O_{2} H$ IV) Butanoic acid, $C_{3} H_{7} C O_{2} H$

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a

$C_{n} H_{n} O_{n}$

b

$C_{n} H_{2 n} O$

c

CHO

d

$C_{n} H_{2 n} O_{2}$

answer is D.

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Detailed Solution

$C_{n} H_{2 n} O_{2}$

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What is the general formula of the homologous series of carboxylic acids?I) Methanoic acid, HCO2H II) Ethanoic acid, CH3CO2HIII) Propanoic acid, C2H5CO2H IV) Butanoic acid, C3H7CO2H