What is the geometry of the${\mathrm{IBr}}_2^{-}$ ion?

Three lone pairs and two bond pairs make up the ${\mathrm{IBr}}_2^{-}$ molecule. According to the bending rule, all lone pairs should be in an equatorial position for ${\mathrm{sp}}^3\mathrm{d}$ hybridization in order to reduce lone pair-lone pair repulsion. If all three lone pairs in ${\mathrm{IBr}}_2^{-}$ are in this position, both $\mathrm{Br}$ will be in conjunction with the axial position, resulting in a linear structure (as all atoms lie in the same line)