What is the hybridization of Te in TeCl⁶

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${sp}^{3} d^{2}$

${sp}^{2}$

$sp$

${sp}^{3} d$

answer is D.

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Detailed Solution

d: sp³d²

Concept Behind Hybridization:

In TeCl₆, tellurium (Te) is in the center of a molecule surrounded by six chlorine atoms. To form six bonds with the chlorine atoms, tellurium needs six hybrid orbitals. The six hybrid orbitals are formed by the combination of one s orbital, three p orbitals, and two d orbitals.

Hence, the hybridization of Te is sp³d².

Key Points:

sp³d² hybridization occurs when there are six bonds, which requires the use of d orbitals.
The geometry of TeCl₆ is octahedral, which corresponds to sp³d² hybridization.