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What is the image distance of a converging mirror which forms a real image of height of $4 cm$ to an object of height $1 cm$ placed $20 cm$ away from the mirror?

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- 80 cm

- 36 cm

- 40 cm

- 42 m

answer is A.

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Detailed Solution

The image distance of a converging mirror which forms a real image of height of

4 cm

to an object of height

1 cm

placed

20 cm

away from the mirror, will be

- 80 cm .

Given,
Distance of the object from the mirror,

u = - 20 cm

Height of the object

{, h}_{0} = 1 cm

Height of the image,

h_{i} = 4 cm

Since

h_{o}

and

h_{i}

is given by using the magnification formula.

m = \frac{h_{i}}{h_{o}} = - \frac{v}{u}

\frac{h_{i}}{h_{o}} = - \frac{v}{u}

\frac{- 4}{1} = - \frac{v}{(- 20)}

v = - 80 cm

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