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Q.
What is the JEE cutoff for IIT Hyderabad?
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Detailed Solution
The JEE Advanced cutoff 2024 for IIT Hyderabad is the minimum rank required for admission to the institute. The cutoff varies by category and course. For the general category, the cutoff for IIT Hyderabad in 2024 is 9303 for B.Tech Civil Engineering, 4976 for B.Tech Mechanical Engineering, and 2117 for B.Tech Electrical Engineering.
For the EWS category, the cutoff is 1436 for B.Tech Civil Engineering, 751 for B.Tech Mechanical Engineering, and 394 for B.Tech Electrical Engineering. For the OBC category, the cutoff is 3484 for B.Tech Civil Engineering, 2354 for B.Tech Mechanical Engineering, and 1072 for B.Tech Electrical Engineering.For the SC category, the cutoff is 1914 for B.Tech Civil Engineering, 1394 for B.Tech Mechanical Engineering, and 692 for B.Tech Electrical Engineering.
For the ST category, the cutoff is 612 for B.Tech Civil Engineering, 540 for B.Tech Mechanical Engineering, and 201 for B.Tech Electrical Engineering.For the PwD category, the cutoff is 176 for B.Tech Civil Engineering, 263 for B.Tech Mechanical Engineering, and 156 for B.Tech Electrical Engineering.These cutoffs are based on the JEE Advanced 2024 exam conducted by IIT Madras on May 26, 2024. The cutoffs will be released on June 9, 2024, along with the results
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