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Q.

What is the limiting reagent in the reaction where NO2 is formed when 0.740 g of O3 reacts with 0.670 g of NO?

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a

NO

b

O2

c

O3

d

NO2

answer is C.

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Detailed Solution

O3 + NO → O2 +NO2

1 mole of O3 reacts with 1 mole of NO.

0.74 g O3 = 0.74 / 48 = 0.0154 mol O3

0.67 g NO = 0.67 / 30 = 0.0223 mol NO

O3 is the limiting reagent and NO is in excess.

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