What is the mass of CO2 that contains 3.011 ×1023 molecules?

We are told that Carbon Dioxide contains 3.011 x 1023 molecules and that we must calculate its mass, for which we have a formula.n= N/NAHere, n represents the number of moles, N represents the number of molecules, and NA is the value of Avogadro's Number, which is 6.022 × 1023.We will obtain this by entering valuesn = 0.5 molWe now understand,n = m/MHere, n represents the number of moles, m represents the substance's mass, and M represents its molecular mass.We have been given The molecular mass of carbon dioxide is 44gms.When we enter values, we getm = 0.5×44 = 22gms

What is the mass of CO2 that contains 3.011 ×1023 molecules?

We are told that Carbon Dioxide contains 3.011 x 1023 molecules and that we must calculate its mass, for which we have a formula.n= N/NAHere, n represents the number of moles, N represents the number of molecules, and NA is the value of Avogadro's Number, which is 6.022 × 1023.We will obtain this by entering valuesn = 0.5 molWe now understand,n = m/MHere, n represents the number of moles, m represents the substance's mass, and M represents its molecular mass.We have been given The molecular mass of carbon dioxide is 44gms.When we enter values, we getm = 0.5×44 = 22gms

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What is the mass of CO₂ that contains 3.011 $\times$ 10²³ molecules?

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44.0 g

4.4 g

11.0 g

22.0 g

answer is B.

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Detailed Solution

We are told that Carbon Dioxide contains 3.011 x 10²³ molecules and that we must calculate its mass, for which we have a formula.
n= N/NA
Here, n represents the number of moles, N represents the number of molecules, and NA is the value of Avogadro's Number, which is 6.022 $\times$ 10²³.
We will obtain this by entering values

n = 0.5 mol

We now understand,
n = m/M
Here, n represents the number of moles, m represents the substance's mass, and M represents its molecular mass.
We have been given The molecular mass of carbon dioxide is 44gms.
When we enter values, we get
m = 0.5×44 = 22gms

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