What is the mass percent of oxygen in the compound UO2C2H3O22NH4C2H3O2⋅6H2O?Formula Weight, gUO2C2H2O22⋅NH4C2H3O2⋅6H2O=573

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What is the mass percent of oxygen in the compound ${UO}_{2} {(C_{2} H_{3} O_{2})}_{2} {NH}_{4} C_{2} H_{3} O_{2} \cdot 6 H_{2} O$ ?

Formula Weight, g

{UO}_{2} {(C_{2} H_{2} O_{2})}_{2} \cdot {NH}_{4} C_{2} H_{3} O_{2} \cdot 6 H_{2} O = 573

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39.1%

22.3%

5.58%

16.8%

answer is D.

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Detailed Solution

Mass percentage is given as,

$\frac{16 \times 14}{573} \times 100 = 39.1 %$

Thus, option D is correct.

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