What is the maximum amount of nitrogen dioxide that can be produced by mixing 4.2 gm of NO(g) and 3.2 gm of O₂ (g)?

Maximum amount of nitrogen dioxide (NO₂) is nothing but find out its weight

Weight (NO₂) = Mole of NO₂ × M. mass of NO₂

$\begin{array}{l}=0.14\times 46\\ =6.44\mathrm{gm}\end{array}$