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Q.

What is the maximum mass of  PbI2 that can be precipitated by mixing 25.0 mL of 0.100 M Pb2NO32 with 35.0 mL  of  0.100 M NaI ?

 Molar mass gmol−1 
PbI2461

 

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a

0.807g

b

2.30g

c

1.15g

d

1.61g

answer is A.

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Detailed Solution

In the reaction we have

PbNO32+2NaI→PbI2↓2.5 3.5 3.52×4611000

Here, maximum mass of PbI2.

3.52×4611000=0.807


 

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