What is the minimum pH required to prevent the precipitation of ZnS in a solution that is 0.01 M $Z n C l_{2}$ and saturated with 0.10 M $H_{2} S$ ? $[G i v e n K_{s p} = 10^{- 21}, K_{a_{1}} \times K_{a_{2}} = 10^{- 20}]$

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Detailed Solution

$K_{s p} = [Z n^{2 +}] [S^{2}] [S^{2}] = \frac{10^{- 21}}{0.01} = 10^{- 19} f o r K_{a_{1}} . K_{a_{2}} = \frac{{[H^{+}]}^{2} [S^{2 -}]}{[H_{2} S]} 10^{- 20} = \frac{{[H^{+}]}^{2} \times 10^{- 19}}{0.1} [H^{+}] = 0.1 o r p H = 1$

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