What is the minimum pH when $Fe {(OH)}_{3}$ starts precipitating from a solution containing 0.1 M ${FeCl}_{3}$ ?
( $K_{s p}$ of $Fe (OH)_{3} = 8 \times 10^{- 13} M^{3}$ )

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8.3

10.3

5.7

3.7

answer is C.

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Detailed Solution

Here, we have $Fe {(OH)}_{3}$ as,

$\begin{array}{ll} [{Fe}^{3 +}] {[{OH}^{-}]}^{3} = 8 \times 10^{- 13} \\ \overset{⇓}{0.1} \\ \Rightarrow [{OH}^{-}] = 2 \times 10^{- 4} M \\ \Rightarrow pH = 10.3 \end{array}$

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