What is the minimum quantity (in grams) of methyl iodide required for preparing one mole of ethane by Wurtz reaction ?

(Atomic weight of iodine = 127)

 The reaction is as follows:

            $2{\mathrm{CH}}_3\mathrm{I}+2\mathrm{Na}\to {\mathrm{C}}_2{\mathrm{H}}_6+2\mathrm{Nal}$

Two moles of methyl iodide are needed for every mole of ethane.

Methyl iodide has a molecular weight of 142 grams.

Thus, 284 grams will be the weight of two moles of methyl iodide.

Hence the correct option is (D).