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What is the minimum thickness of a thin film required for constructive interference in the reflected light from it ? Given: R.I. of the film = 1.5, wavelengths of the light incident on the film = 600 nm.

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50 nm

200 nm

300 nm

100 nm

answer is A.

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Detailed Solution

$2 μtcos r = (2 n + 1) \frac{λ}{2}$ , where n=0, 1, 2, 3....

For minimum thickness $n = 0$ .

For near normal incidence $r \approx 0^{\circ}$ .

$∴ t_{min} = \frac{(2 \times 0 + 1) λ}{4 \cdot μ \cdot \cos 0^{o}}$

$= \frac{600}{4 \times 1 .5} nm = 100 nm$

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