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Q.

What is the minimum $p^{H}$ required to prevent the precipitation of ZnS in a solution that is $0.01 M Z n C l_{2} a n d s a t u r a t e d w i t h 0.1 M H_{2} S ?$
$[G i v e n : K_{s p} o f Z n S = 10^{- 21}, K_{a 1} \times K_{a 2} = 10^{- 20}]$

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a

1

b

4

c

0

d

3

answer is B.

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Detailed Solution

$K_{sp} = [{Zn}^{+ 2}] [S^{- 2}] = 10^{- 21}, [S^{- 2}] = \frac{[10^{- 21}]}{[0.01]} = 10^{- 19}, For H_{2} S, K_{a 1} \times K_{a 2} = \frac{{[H^{+}]}^{2} [S^{- 2}]}{[H_{2} S]} = 10^{- 20} {[H^{+}]}^{2} = \frac{0.1 \times 10^{- 20}}{10^{- 19}} = 0.01, Hence, [H^{+}] = 0.1 Therefore, p^{H} = 1$

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