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What is the molarity of $H_{2} {SO}_{4}$ solution that has a density of $1.84 g / cc$ and contains $98 %$ by mass of $H_{2} {SO}_{4} ?$

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4.18 M

8.14 M

18.4 M

18 M

answer is C.

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Detailed Solution

volume $= \frac{100}{1.84} mL = \frac{100}{1.84 \times 1000} L$

Now molarity $= \frac{weight given}{molecular wt \times volume}$

$\begin{array}{l} = \frac{98 \times 1.84 \times 1000}{98 \times 100} \\ = 18.4 M \end{array}$

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