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Q.

What is the mole percentage of $O_{2}$ in a mixture of 7g of $N_{2}$ and 8g of $O_{2}$

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a

25%

b

40%

c

75%

d

50%

answer is C.

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Detailed Solution

7 gms of $N_{2} = \frac{7}{28}$

= 0.25 moles

8 gms of $O_{2} = \frac{8}{32}$

= 0.25 moles

$∴$ mole percent $O_{2} = \frac{0.25}{0.5} \times 100 = 50 %$

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