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What is the moment of inertia of a rod of mass M, length $l$ about an axis perpendicular to its length and passing through one end

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$\frac{M}{3}$

$\frac{M l}{2}$

$\frac{M l^{2}}{2}$

$\frac{M l^{2}}{3}$

answer is A.

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Detailed Solution

$\begin{array}{l} I = \frac{{ML}^{2}}{12} + M (L / 2)^{2} \\ I = \frac{{ML}^{2}}{3} \end{array}$

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