Q.

What is the neutralization reaction between HCl(aq) and KOH(aq)?

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a

HCl(aq) + KOH(aq) → 2H2O(l) + KCl(aq)

b

HCl(aq) + KOH(aq) → H2O(l) + KCl(aq)

c

HCl(aq) + KOH(aq) → H2O(l) + KCl(aq)

d

HCl(aq) + KOH(aq) → H2O(l) + 2KCl(aq)

answer is A.

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Detailed Solution

The chemical equation for the reaction between HCl(aq) and KOH(aq) is-                                                     HCl(aq) + KOH(aq) → H2O(aq) + KCl(aq)

Check for balancing of the chemical equation-

Balancing of H-

Number of H on the reactant side = Number of H on the product side

2=2

Hence, the H element is already balanced. 

Balancing of K-

Number of K on the reactant side = Number of K on the product side

1=1

Hence, the K element is also already balanced.

Balancing of O-

Number of O on the reactant side = Number of O on the product side

1=1

Hence, O is also already balanced.

Balancing of Cl-

Number of chlorine on the reactant side= Number of chlorine on the product side

1=1

Hence, chlorine is also already balanced.

Balancing of the total number of elements -

Total number of elements  on the reactant side = Total number of elements on the product side

5=5

Hence this reaction is already balanced.

So, the correct answer is-

    HCl(aq) + KOH(aq) → H2O(aq) + KCl(aq)

 

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