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What is the normality of the $H_{2} {SO}_{4}$ solution, 18.6 mL of which neutralizes 30.0 mL of a 1.55 N $KOH$ solution?

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3.5 N

5.0 N

2.5 N

1.25 N

answer is C.

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Detailed Solution

$N \times 18.6 = 30.0 \times 1.55$

$N = \frac{30 \times 1.55}{18.6}$

$N = 2.5$

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