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What is the number of digits in the square root of 24025?

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answer is A.

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Detailed Solution

The given number is 24025.
The square root of an n-digit perfect square will have,

n 2

digits if n is even.

n + 1 2

digits if n is odd.
The number of digits in 24025 = 5.
Using the above formula, the square root of 24025 will have,

⇒ 5 + 1 2 = 3

Hence, 24025's square root will be a three-digit number.
Therefore, option 1 is correct.

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