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What is the number of divisors of 1296 excluding 1 & itself

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answer is B.

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Detailed Solution

2 | 1296
2 | 648
18 | 324
| 18

∴ Prime factor = 2 × 2 × 18 × 18
= 2 × 2 × (2 × 3 × 3) × (2 × 3 × 3)
= 2⁴ × 3⁴

No. of divisions = (4+1) × (4+1) (Excluding '1' & itself)
= 25 – 2 = 23

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