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Q.

What is the number of electrons gained at the cathode when 1.08g silver is electroplated on a metal tray

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a

$6.023 \times 10^{23} \times 1.08$

b

$6.022 \times 10^{20}$

c

$\frac{6.023 \times 10^{23} \times 1.08}{108}$

d

$\frac{6.023 \times 10^{23}}{1.08}$

answer is B.

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Detailed Solution

For $108 g of Ag_____6.023 \times 10^{23} e^{-}$

$1.08 g of Ag_________x$

$x = \frac{6.023 \times 10^{23} \times 1.08}{108}$

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