What is the % of ionic character of HBr when the dipole moment of HBr is 1.6×10−30 cm and interatomic spacing is 1A°

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What is the % of ionic character of HBr when the dipole moment of HBr is $1.6 \times 10^{- 30}$ cm and interatomic spacing is $1 A °$

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answer is 10.

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Detailed Solution

% of ionic character $= \frac{o b s e r v e d d i p o l e m o m e n t}{c a l c u l a t e d d i p o l e m o m e n t} \times 100$ $= \frac{1.6 \times 10^{- 30}}{1.6 \times 10^{- 19} \times 10^{- 10}} \times 100 = 10$

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