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What is the order of reaction for which rate becomes half if volume of the container having same amount of reactant is doubled? Assume gaseous phase reaction.

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answer is 1.

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Detailed Solution

$Rate = [a]^{n}; Case I: r_{1} = k {[\frac{a}{V}]}^{n}$
$Case II : \frac{r_{1}}{2} = k {[\frac{a}{2 V}]}^{n}$
By Eqs (i) and (ii) (2)¹ = (2)ⁿ; $∴$ n = 1

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