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Q.

What is the oxidation state of 'Fe' in the product formed when acidified potassium ferrocyanide K4[Fe(CN)6] is treated with hydrogen peroxide?

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a

+1

b

+2

c

+6

d

+3

answer is B.

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Detailed Solution

In K4[Fe(CN)6] Ox.state of 'Fe' is +2

[Fe(CN)6]-4
x + 6(-1) = -4
x = +2
H2O2 Oxidises K4[Fe(CN)6] to K3[Fe(CN)6] in acidic medium

  In  K3[Fe(CN)6] ,

[Fe(CN)6]-3
x +6(-1) = -3
x = +3

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