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What is the oxidation state of ‘Fe’ in the product formed when acidified potassium ferrocyanide K₄[Fe(CN)₆] is treated with hydrogen peroxide?

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answer is B.

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Detailed Solution

$K_{4} [\overset{+ 2}{Fe} {(CN)}_{6}] + H_{2} {SO}_{4} + H_{2} O_{2} \to K_{3} [\overset{+ 3}{Fe} {(CN)}_{6}] + K_{2} {SO}_{4} + H_{2} O$

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