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What is the percentage dissociation of a substance if its vapour densities before and after dissociation are 30 and 15 respectively and 1 mole of its dissociation to 3 moles of products?

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25%

50%

65%

75%

answer is B.

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Detailed Solution

$α = \frac{D - d}{d (n - 1)} = \frac{30 - 15}{15 (3 - 1)} = \frac{15}{2 \times 15} = \frac{1}{2} \times 100 = 50 %$

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