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Q.

What is the pH of a solution obtained by dissolving 0.0005 mole of the strong electrolyte, calcium hydroxide, Ca(OH)2 to form 100 ml of a saturated solution (aqueous)?
    (Kw = 1.0 × 10–14 mole2litre–2)   

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a

12.0

b

9.8

c

3.0

d

11.7

answer is C.

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Detailed Solution

Ca(OH)2=5×10-4100×10-3

∴OH-=2×5×10-1100=10-2

[H+] = 10-12

PH = 12

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