Q.

What is the pH of a solution obtained by dissolving 0.0005 mole of the strong electrolyte, calcium hydroxide, Ca(OH)2to form 100 ml of a saturated solution (aqueous)?KW=1.0×10-14 mole2Liter-2

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a

12.0

b

3.0

c

9.8

d

11.7

answer is C.

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Detailed Solution

M=n×1000V(mL)

n = 0.0005

Ca(OH)2; Electron. F = 2[Base's Acidity ]

M=0.005×1000100=0.005

N=n1(M)

=2(0.005)=10-2M

POH=-log10OH=-log1010-2=2

pH = pOH = 14

pH = 14 − 2 = 12

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What is the pH of a solution obtained by dissolving 0.0005 mole of the strong electrolyte, calcium hydroxide, Ca(OH)2to form 100 ml of a saturated solution (aqueous)?KW=1.0×10-14 mole2Liter-2