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Q.

What is the phenotypic ratio incase of duplicate dominant epistasis?

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a

9:7

b

9:3:4

c

12:3:4

d

15:1

answer is C.

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Detailed Solution

Incase of duplicate dominant epistasis the normal 9:3:3:1 is modified to give the ratio of 15:1, in this case 1/16 represents homozygous recessive condition.

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