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What is the potential energy of the electron in the first excited state of hydrogen atom?

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-6.8 ev

-3.4 ev

-10.2 ev

-1.52 ev

answer is A.

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Detailed Solution

Total energy of the electron in the first excited state of hydrogen atom is $- \frac{13.6}{2^{2}} ev i . e ., - 3.4 ev$

$∴$ potential energy = -2 x 3.4 ev = -6.8 ev

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