What is the power of accommodation of the eye of a human of normal eyesight?

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1 D

2 D

3 D

4 D

answer is D.

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Detailed Solution

The power of accommodation of the eye of a human of normal eyesight is

4 D

.
It is known that the power of a lens is the reciprocal of the focal length of the lens. Mathematically,

P = \frac{100}{f}

Where

f

is the focal length of the lens in centimetres.
It is known that the near point of the normal human eye is

25 cm

, which can be considered its focal length.
On substituting the focal length, we get the power as

\Rightarrow P = \frac{100}{25}

\Rightarrow P = 4 D

Hence, the power of accommodation of the eye of a human of normal eyesight is

4 D

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