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Q.

What is the principal solution of 2sin x + 1 = 0

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a

$\frac{π}{6}$

b

$- \frac{π}{6}$

c

$\frac{π}{4}$

d

$- \frac{π}{4}$

answer is B.

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Detailed Solution

$\begin{array}{l} 2 \sin x + 1 = 0 \\ 2 \sin x = - 1 \\ \sin x = - 1 / 2 \\ \sin x = \sin (- \frac{π}{6}) \end{array}$

$x = - \frac{π}{6}$ is the principal solution

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