What is the probability of getting an even number, when a die is thrown once ?

It is given that a die is thrown once and we need to find the probability of getting an even number.

It is known that when a dice is thrown once, it has a possible number of outcomes as 6¹= 6 . The sample space (S) is given as

$\mathrm{S}=\left\{1,2,3,4,5,6\right\}$

Out of these, the even numbers are $\left\{2,4,6\right\}=3$

Now, the probability of an event (E), denoted by P(E), is given by the ratio of the number of favorable outcomes to the number of the possible outcomes/the number of elements in sample space. Mathematically,

$\mathrm{P}\left(\mathrm{E}\right)=\frac{\mathrm{number} \mathrm{of} \mathrm{favourable} \mathrm{outcomes}}{\mathrm{number} \mathrm{of} \mathrm{the} \mathrm{possible} \mathrm{outcomes}/\mathrm{the} \mathrm{number} \mathrm{of} \mathrm{elements} \mathrm{in} \mathrm{sample} \mathrm{space}}$In the given case, the event is that the number is even. Its probability is calculated as

$\mathrm{P}=(\mathrm{even} \mathrm{number})=\frac{3}{6}$

$\Rightarrow \mathrm{P}(\mathrm{even} \mathrm{number})=\frac{1}{2}$