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Q.

What is the product obtained when $M n O_{2}$ solution is boiled with $P b O_{2}$ and concentrated ${HNO}_{3}$

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a

${MnO}_{2}$

b

${Mn}_{3} O_{4}$

c

${PbMnO}_{4}$

d

${HMnO}_{4}$

answer is B.

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Detailed Solution

$\begin{array}{l} 2 {MnO}_{2} + 4 {HNO}_{3} ⟶ 2 Mn {({NO}_{3})}_{2} + O_{2} \\ 2 Mn {({NO}_{3})}_{2} + {PbO}_{2} + {HNO}_{3} \to {HMnO}_{4} + Pb {({NO}_{3})}_{2} + H_{2} O \end{array}$

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