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Q.

What is the relation between accelerations of points A and B is the given 

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a

aB=aAcotθ

b

aB=aAsecθ

c

aB=aAtanθ

d

aA=aBcosθ

answer is B.

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Detailed Solution

From the constraint relation, the accelerations of the bodies in perpendicular direction to the point of contact of the surfaces should be same.

Let the acceleration of A and B be aA and aB respectively.

The components of the acceleration along the common normal must be equal.

aAcos(90-θ)=aBcosθ

aB=aA  tan  θ

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