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Q.

What is the serial number of a boy in the middle of the row of 45 boys?


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a

21

b

22

c

23

d

24 

answer is C.

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Detailed Solution

Concep- We will first comprehend how the lads are organized. After that, we'll decide how to rank the boys. We may choose between two strategies once we've determined which side will serve as the row's beginning and ending points. For any number of things, or guys in our example, in the row, we may create a formula, or we can manually count. We shall attempt to obtain the formula for our query. Once the formula has been created, we may enter the number of boys to obtain the middle position's rank or serial number.
We are informed that there are 45 lads lined up in a row. We may infer that they are arranged in a single row from the term "row." We therefore have a starting point and an ending point in a linear arrangement. We will use the left end of the row as the starting point and the right end as the ending point for our calculation.
Accordingly, the child at the leftmost end will have serial number 1, the next boy will have serial number 2, and so on until the boy at the rightmost end, who will have serial number 45.
1 2 3 … 45
Now, to generalize, assume that there are 2n + 1 items in a row. It is obvious that there are an unusually large number of objects.
The center phrase now denotes the presence of an equal item to its right and left. In two configurations of the maximum equal number of 2n + 1 things, there will be n items total. As a result, there will be 1 item remaining, with n things to the left and n items to the right. This middle term's position will be (n+1).
But (n + 1), or (2n + 1 + 1), makes up half of (2n + 2) instead.
Hence, the position of middle term if we have 2n+1   items in a row is 2n+1+1 2  .
We know that for our question, 2n+1=45  .
Therefore, the position and hence serial number of the middle term will be 45+1 2 =23  .
Hence, option 3 is correct.
 
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