What is the shape of Fe(CO)5 molecule? Given that its dipole moment = 0.

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What is the shape of $Fe {(CO)}_{5}$ molecule? Given that its dipole moment = 0.

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Tetrahedral

Trigonal bipyramidal

Square pyramidal

Octahedral

answer is C.

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Detailed Solution

Since the Fe-atom is in a $d s p^{3}$ hybridized state. $Fe (CO)_{5}$ has a trigonal bipyramidal structure because
The hybridization is as follows:

$26 Fe = 1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{6} 3 d^{6}, 4 s^{2} 4 p^{2}$

Hence, the correct option is C.

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