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What is the shortest wavelength line in the Paschen series of $L i^{2 +}$ ion?

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$\frac{1}{R}$

$\frac{9 R}{4}$

$\frac{9}{R}$

$\frac{R}{9}$

answer is C.

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Detailed Solution

$\frac{1}{λ} = R Z^{2} (\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}) n_{1} = 3; n_{2} = \propto; Z_{L i^{+}} = 3 \frac{1}{λ} = R \times 3^{2} (\frac{1}{3^{2}}) λ = \frac{1}{R}$

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