What is the smallest 4-digit number that is divisible by 18, 24 and 32?

The given numbers are 18, 24, and 32.
To find, the smallest 4-digit number that is divisible by 18, 24, and 32.
Prime factorization of 18, 24, 32 is,

Here, $2 \times 2 \times 2 \times 2 \times 2 \times 3 \times 3 = 288$.
LCM of 18, 24, 32 is 288.
Using the multiples of the LCM value, we can get the smallest four-digit number.
288 × 1 = 288
288 × 2 = 576
288 × 3 = 864
288 × 4 = 1152
Here, 1152 is the smallest 4-digit multiple of 288, and it is exactly divisible by 18, 24, and 32.