What is the solubility of $A l {(O H)}_{3} i f K_{S P} = 1 X 10^{- 33}$ in a solution having $P^{H} = 4$

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$10^{- 3} m$

$10^{- 6} m$

$10^{- 4} m$

$10^{- 10} m$

answer is A.

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Detailed Solution

$\begin{array}{l} P^{H} = 4, P^{O H} = 10 \\ [O \bar{H}] = 10^{- 10} \\ K_{S P} = [A l^{+ 3}] {[O \bar{H}]}^{3} \\ ∴ [A l^{+ 3}] = \frac{1 X 10^{- 33}}{{[10^{- 10}]}^{3}} \end{array}$

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