What is the specific heat capacity of mercury (in J x $g^{- 1} \times^{\circ} C^{- 1})$ if a 25.0 g sample requires 19.3 J to raise its temperature from 24.5° C to 30.0° C?

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7.1

0.14

0.026

0.032

answer is C.

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Detailed Solution

It is known that,

$q = m s ∆ T$

$\begin{array}{l} 19.3 = 25 \times 5 \times (30 - 24 \cdot 5) \\ 19.3 = 25 \times 5 \times 5.5 \\ s = \frac{19.3}{137.5} \\ S = 0.14 \\ J^{- 1} {g^{- 1}}^{\circ} C^{- 1} \end{array}$

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