What is the spin-only magnetic moment value (BM) of a divalent metal ion with atomic number 25, in its aqueous solution?

${\mathrm{Mn}}^{2+} = 1{\mathrm{s}}^{2}2{\mathrm{s}}^2 2{\mathrm{p}}^{6}3{\mathrm{s}}^{2}3 {\mathrm{p}}^{6}3{\mathrm{d}}^5$
So , unpaired number of electrons = 5
Spin magnetic moment $\sqrt{\mathrm{n}(\mathrm{n}+2)} =\sqrt{5(5+2)} =\sqrt{35} =5.92 \mathrm{BM}$
Hence , the magnetic moment = 5.92 BM