What is the stress developed inside a tooth cavity filled with copper when hot tea at temperature of 57∘C is drunk. You can take body (tooth) temperature to be 37∘C and α=1.7×10−5/∘C, bulk modulus for copper =140×109N/m2.

Stress=B × volume strain =B(ΔVV)=B(3αΔT)

What is the stress developed inside a tooth cavity filled with copper when hot tea at temperature of 57∘C is drunk. You can take body (tooth) temperature to be 37∘C and α=1.7×10−5/∘C, bulk modulus for copper =140×109N/m2.

Stress=B × volume strain =B(ΔVV)=B(3αΔT)

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What is the stress developed inside a tooth cavity filled with copper when hot tea at temperature of $57^{\circ} C$ is drunk. You can take body (tooth) temperature to be $37^{\circ} C$ and $α = 1.7 \times 10^{- 5} /^{\circ} C$ , bulk modulus for copper $= 140 \times 10^{9} N / m^{2}$ .

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$1.428 \times 10^{10} N / m^{2}$

$1.428 \times 10^{8} N / m^{2}$

$1.428 \times 10^{9} N / m^{2}$

$1.428 \times 10^{11} N / m^{2}$

answer is A.

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Stress=B $\times$ volume strain = $B (\frac{Δ V}{V}) = B (3 α Δ T)$

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What is the stress developed inside a tooth cavity filled with copper when hot tea at temperature of 57∘C is drunk. You can take body (tooth) temperature to be 37∘C and α=1.7×10−5/∘C, bulk modulus for copper =140×109N/m2.

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What is the stress developed inside a tooth cavity filled with copper when hot tea at temperature of $57^{\circ} C$ is drunk. You can take body (tooth) temperature to be $37^{\circ} C$ and $α = 1.7 \times 10^{- 5} /^{\circ} C$ , bulk modulus for copper $= 140 \times 10^{9} N / m^{2}$ .